2(5y-1)(y-3)=10y^2-32y+6

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Solution for 2(5y-1)(y-3)=10y^2-32y+6 equation: 



2(5y-1)(y-3)=10y^2-32y+6

We move all terms to the left:

2(5y-1)(y-3)-(10y^2-32y+6)=0

We get rid of parentheses

-10y^2+2(5y-1)(y-3)+32y-6=0

We multiply parentheses ..

-10y^2+2(+5y^2-15y-1y+3)+32y-6=0

We multiply parentheses

-10y^2+10y^2-30y-2y+32y+6-6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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